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8m^2-9=567
We move all terms to the left:
8m^2-9-(567)=0
We add all the numbers together, and all the variables
8m^2-576=0
a = 8; b = 0; c = -576;
Δ = b2-4ac
Δ = 02-4·8·(-576)
Δ = 18432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{18432}=\sqrt{9216*2}=\sqrt{9216}*\sqrt{2}=96\sqrt{2}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96\sqrt{2}}{2*8}=\frac{0-96\sqrt{2}}{16} =-\frac{96\sqrt{2}}{16} =-6\sqrt{2} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96\sqrt{2}}{2*8}=\frac{0+96\sqrt{2}}{16} =\frac{96\sqrt{2}}{16} =6\sqrt{2} $
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